3x^2+11x+10=(3x+5)(x+2)

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Solution for 3x^2+11x+10=(3x+5)(x+2) equation: 



3x^2+11x+10=(3x+5)(x+2)

We move all terms to the left:

3x^2+11x+10-((3x+5)(x+2))=0

We multiply parentheses ..

3x^2-((+3x^2+6x+5x+10))+11x+10=0



We calculate terms in parentheses: -((+3x^2+6x+5x+10)), so:

(+3x^2+6x+5x+10)

We get rid of parentheses

3x^2+6x+5x+10

We add all the numbers together, and all the variables

3x^2+11x+10

Back to the equation:

-(3x^2+11x+10)



We add all the numbers together, and all the variables

3x^2+11x-(3x^2+11x+10)+10=0

We get rid of parentheses

3x^2-3x^2+11x-11x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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